4x^2+10=179

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Solution for 4x^2+10=179 equation:



4x^2+10=179
We move all terms to the left:
4x^2+10-(179)=0
We add all the numbers together, and all the variables
4x^2-169=0
a = 4; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·4·(-169)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52}{2*4}=\frac{-52}{8} =-6+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52}{2*4}=\frac{52}{8} =6+1/2 $

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